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x^2-712x+49936=0
a = 1; b = -712; c = +49936;
Δ = b2-4ac
Δ = -7122-4·1·49936
Δ = 307200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{307200}=\sqrt{102400*3}=\sqrt{102400}*\sqrt{3}=320\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-712)-320\sqrt{3}}{2*1}=\frac{712-320\sqrt{3}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-712)+320\sqrt{3}}{2*1}=\frac{712+320\sqrt{3}}{2} $
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